COPA Case: Final Arguments in BTC Claims Against Craig Wright

The Crypto Open Patent Alliance (COPA) has begun presenting its closing arguments in a lawsuit against Craig Wright, who claims to be Bitcoin inventor Satoshi Nakamoto. COPA is seeking injunctive relief to prevent Wright from claiming to be Nakamoto. The burden of proof lies with COPA to show that Wright is not Nakamoto. COPA alleges that Wright engaged in massive forgery of documents to support his claim. They also plan to have the documents submitted by Wright considered for perjury charges. The trial began on February 5, and Wright had previously offered to settle out of court but was declined by COPA. COPA was founded in 2020 with the goal of removing patents as a barrier to cryptocurrency innovation and has notable members such as Coinbase and Kraken.

Wright holds many patents related to blockchain technology, which introduces the topic of intellectual property rights into the trial. In 2023, Wright sued several Bitcoin Core developers and companies for copyright violations regarding the Bitcoin white paper and its file format. The Bitcoin Legal Defense Fund has expressed concern about these lawsuits, stating that they deter developers from working on Bitcoin due to the time, stress, money, and legal risk involved. Wright filed for United States copyright registration for the Bitcoin white paper in 2019 and currently has an active case in the United Kingdom over its rights. The white paper is now under the MIT open-source license, meaning anyone can reuse and modify it. A court injunction would prevent Wright from making further copyright claims on it.

COPA is making its case against Wright in an attempt to prove that he is not Satoshi Nakamoto, accusing him of forging documents and fabricating a biographical history. The trial is expected to continue for several days as COPA presents its arguments. The outcome of the case could have implications for intellectual property rights surrounding blockchain technology and the legitimacy of Wright’s claims.

Hanan Escamilla

Hanan Escamilla

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